2sin^2[x]+5sin[x]+2=0

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Solution for 2sin^2[x]+5sin[x]+2=0 equation:


Simplifying
2sin2[x] + 5sin[x] + 2 = 0

Multiply in2s * x
2in2sx + 5sin[x] + 2 = 0

Multiply ins * x
2in2sx + 5insx + 2 = 0

Reorder the terms:
2 + 5insx + 2in2sx = 0

Solving
2 + 5insx + 2in2sx = 0

Solving for variable 'i'.

Move all terms containing i to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + 5insx + -2 + 2in2sx = 0 + -2

Reorder the terms:
2 + -2 + 5insx + 2in2sx = 0 + -2

Combine like terms: 2 + -2 = 0
0 + 5insx + 2in2sx = 0 + -2
5insx + 2in2sx = 0 + -2

Combine like terms: 0 + -2 = -2
5insx + 2in2sx = -2

Reorder the terms:
2 + 5insx + 2in2sx = -2 + 2

Combine like terms: -2 + 2 = 0
2 + 5insx + 2in2sx = 0

The solution to this equation could not be determined.

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